SOLUTION: For what real values of c is x^2 + 16x + c the square of a binomial? If you find more than one, then list your values separated by commas.
Algebra ->
Quadratic Equations and Parabolas
-> SOLUTION: For what real values of c is x^2 + 16x + c the square of a binomial? If you find more than one, then list your values separated by commas.
Log On
Question 1085953: For what real values of c is x^2 + 16x + c the square of a binomial? If you find more than one, then list your values separated by commas. Found 2 solutions by Boreal, MathLover1:Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! take half of 16 and square it, so c=64
x^2+16x+64 is (x+8)^2. (8, 8) multiplicity of roots.
the vertex of this quadratic is at -b/2a for x, or x=-16/2=-8. y=-64+128, and c must be 64.
You can put this solution on YOUR website!
For what real values of is the square of a binomial?
recall the square of a binomial:
you have -> , , and
find -> -> ->
then, ->
