SOLUTION: 1. Find the area in simplified form for a rectangle with a length of \sqrt{24} and a width of \sqrt{18} 2. What is the area for a rectangle with a base of \sqrt{3}x^3y^2 and len

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: 1. Find the area in simplified form for a rectangle with a length of \sqrt{24} and a width of \sqrt{18} 2. What is the area for a rectangle with a base of \sqrt{3}x^3y^2 and len      Log On


   

Question 1085868: 1. Find the area in simplified form for a rectangle with a length of \sqrt{24} and a width of \sqrt{18}
2. What is the area for a rectangle with a base of \sqrt{3}x^3y^2 and length \sqrt{6}xy^3.
Found 2 solutions by rapture, ikleyn:
Answer by rapture(86) About Me  (Show Source):
You can put this solution on YOUR website!
A = L•W


Part 1


A = sqrt{24}•sqrt{18}


A = sqrt{24 • 18}


A = sqrt{432}


A = 20.7846096908


A = 20.8


Part 2


A = [sqrt{3}•x^3•y^2][sqrt{6}•x•y^3]


A = sqrt{3•6}•x^4•y^5


A = sqrt{18}•x^4•y^5


A = sqrt{9}•sqrt{2}•x^4•y^5


A = 3•sqrt{2}•x^4•y^5



Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.
Part 1. 
sqrt%2824%29%2Asqrt%2818%29 = sqrt%282%5E3%2A3%29.sqrt%283%5E2%2A2%29 = sqrt%282%5E4%2A3%5E3%29 = 4%2A3%2Asqrt%283%29 = 12%2Asqrt%283%29 = 20.7846.