SOLUTION: 4x^2-20x+41=0

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Question 1078714: 4x^2-20x+41=0
Found 2 solutions by Boreal, ikleyn:
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
4x^2-20x+41=0
x=(1/8)(20+/- sqrt (400-656); sqrt (-256)=16 i
x=(20/8)+/- 2i
x=2.5 +/- 2i
graph%28300%2C300%2C-10%2C10%2C-50%2C50%2C4x%5E2-20x%2B41%29

Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.
On solution quadratic equations using the quadratic formula see the lessons
    - Introduction into Quadratic Equations
    - PROOF of quadratic formula by completing the square
in this site.


It is SO BASIC SUBJECT in the school Math that EVERY student MUST it know along and across.