SOLUTION: c=5/9(f-32) need to isolate for f

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Question 107572: c=5/9(f-32) need to isolate for f
Found 2 solutions by checkley71, bucky:
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
C=5/9(F-32)
C=(5F-160)/9 NOW CROSS MULTIPLY
5F-160=9C ADD 160 TO BOTH SIDES
5F=9C+160 NOW DIVIDE BY 5
F=9C/5+32

Answer by bucky(2189) About Me  (Show Source):
You can put this solution on YOUR website!
Given the equation:
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C+=+%285%2F9%29%28F+-+32%29
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To solve this equation for F begin by doing the distributed multiplication on the right side.
By that you multiply 5%2F9 times each of the two terms in the parentheses. The multiplication
of %285%2F9%29 and F results in %285%2F9%29%2AF and the multiplication of %285%2F9%29 and -32
results in -%285%2F9%29%2A32. So the equation becomes:
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C+=+%285%2F9%29%2AF+-+%285%2F9%29%2A32
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Get rid of the -%285%2F9%29%2A32 on the right side by adding %2B%285%2F9%29%2A32 to both sides. This
addition cancels the -%285%2F9%29%2A32 on the right side. And after the addition to the left side
the equation becomes:
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C+%2B+%285%2F9%29%2A32+=+%285%2F9%29%2AF
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Next multiply both sides (all terms) by 9%2F5 to get rid of the fractions. This multiplication
of all terms results in:
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%289%2F5%29%2AC+%2B+%289%2F5%29%2A%285%2F9%29%2A32+=+%289%2F5%29%2A%285%2F9%29%2AF
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Notice that when you multiply 9%2F5 times 5%2F9 the result is 1. This makes
the equation become:
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%289%2F5%29%2AC+%2B+1%2A32+=+1%2AF
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which multiplies out to give:
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%289%2F5%29%2AC+%2B+32+=+F
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And reversing the sides this is:
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F+=+%289%2F5%29%2AC+%2B+32
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This is the answer to your problem. Hope that it helps you to understand the problem a
little better.
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