SOLUTION: The length of a rectangle is 2 feet longer than the width. The area of the rectangle is 8 square feet. Draw the graph of the function A(w) that represents this problem. Determine t

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: The length of a rectangle is 2 feet longer than the width. The area of the rectangle is 8 square feet. Draw the graph of the function A(w) that represents this problem. Determine t      Log On


   

Question 1075030: The length of a rectangle is 2 feet longer than the width. The area of the rectangle is 8 square feet. Draw the graph of the function A(w) that represents this problem. Determine the maxima or minima.

Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
L=W+2
A=(W+2)(W)=W^2+2W=8
W^2+2W-8=0
(W+4)(W-2)=0
W=2 only positive root.
L=4
Minimum at w=-1, function= -9
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