SOLUTION: I need help with this kind of problem:
Find the vertex, the y-intercept, and symmetric point, and use these to sketch a graph.
y=2x^2 -11x -12
I am having problems solving for t
Algebra ->
Quadratic Equations and Parabolas
-> SOLUTION: I need help with this kind of problem:
Find the vertex, the y-intercept, and symmetric point, and use these to sketch a graph.
y=2x^2 -11x -12
I am having problems solving for t
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Question 107371: I need help with this kind of problem:
Find the vertex, the y-intercept, and symmetric point, and use these to sketch a graph.
y=2x^2 -11x -12
I am having problems solving for the vertex. Found 2 solutions by Annabelle1, MathTherapy:Answer by Annabelle1(69) (Show Source):
You can put this solution on YOUR website! This is a quadratic. There is a formula you can use to find the vertex.
this will give you the line of symmetry which is also the x value of the vertex.
Sub the x value bank into your original equation to find the y value.
I need help with this kind of problem:
Find the vertex, the y-intercept, and symmetric point, and use these to sketch a graph.
y=2x^2 -11x -12
I am having problems solving for the vertex.
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Formula for the x-coordinate of the vertex of a parabola: . Compare to:
In this case, b = - 11, and a = 2.
So, the x-coordinate of the vertex of THIS parabola is:
Now, substitute the x-value into the ORIGINAL equation to get the y-coordinate of the vertex, as follows:
<==== y-coordinate of the vertex of THIS parabola
Vertex of parabolic equation, :
(
