SOLUTION: Find the vertex of the graph of the quadratic function. Determine whether the graph opens upward or​ downward, find any​ intercepts, and sketch the graph. f(x)=-x

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Find the vertex of the graph of the quadratic function. Determine whether the graph opens upward or​ downward, find any​ intercepts, and sketch the graph. f(x)=-x      Log On


   



Question 1073647:
Find the vertex of the graph of the quadratic function. Determine whether the graph opens upward or​ downward, find any​ intercepts, and sketch the graph.
f(x)=-x^2-2x+3
A. The vertex is:
B. The parabola opens downward or upward
C. The x-intercepts are:
D. The Y-intercepts are:
E; Graph

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Find the vertex of the graph of the quadratic function. Determine whether the graph opens upward or​ downward, find any​ intercepts, and sketch the graph.
f(x)=-x^2-2x+3
A. The vertex is:
x = -b/(2a) = 2/(-2) = -1
y = f(-1) = -1+2+3 = 4
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B. The parabola opens downward or upward
Down because a = -1
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C. The x-intercepts are:
Solve -x^2-2x+3 = 0
x^2 + 2x - 3 = 0
(x+3)(x-1) = 0
x = -3 or x = 1
Intercepts:: (-3,0) ; (1,0)
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D. The Y-intercepts are:
f(0) = -0^2-2*0+3 = 3
Intercept:: (0,3)
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E; Graph
Plot the points and sketch the parabola.
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Cheers,
Stan H.
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