SOLUTION: Draw a rough sketch of the quadradic function. Label the vertex and any x and y intercepts.
f(x)=-2(x-3)2+8 (that is (x-3) squared)
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Quadratic Equations and Parabolas
-> SOLUTION: Draw a rough sketch of the quadradic function. Label the vertex and any x and y intercepts.
f(x)=-2(x-3)2+8 (that is (x-3) squared)
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Question 107171: Draw a rough sketch of the quadradic function. Label the vertex and any x and y intercepts.
f(x)=-2(x-3)2+8 (that is (x-3) squared) Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Draw a rough sketch of the quadratic function. Label the vertex and any x and y intercepts.
f(x)=-2(x-3)^2+8
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Notice that f(3) is 8.
That is the vertex.
Notice that -2(x-3)^2 is always negative for all values of x
so the parabola opens down from the vertex.
Notice that when x=0, y = 2*9+8 = 26; that is the y-intercept.
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Cheers,
Stan H.
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