SOLUTION: Find the value of the discriminant and determine the number of real-number solutions for this quadratic equation. y^2+3y-4=0
[0,one] [25,two] [30,one]
Can someone tell me how i
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-> SOLUTION: Find the value of the discriminant and determine the number of real-number solutions for this quadratic equation. y^2+3y-4=0
[0,one] [25,two] [30,one]
Can someone tell me how i
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Question 1068569: Find the value of the discriminant and determine the number of real-number solutions for this quadratic equation. y^2+3y-4=0
[0,one] [25,two] [30,one]
Can someone tell me how i find out which answer to pick and why Found 2 solutions by Alan3354, ikleyn:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! Find the value of the discriminant and determine the number of real-number solutions for this quadratic equation. y^2+3y-4=0
[0,one] [25,two] [30,one]
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y^2+3y-4=0
It's in the form ax^2 + bx + c = 0
a = 1, b = 3, c = -4
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The Disc is b^2 - 4ac
Disc = 3^2 - 4*1*(-4) = 9 +16 = 25
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Disc < 0 --> no real roots
Disc = 0 --> 2 real roots that are equal
Disc > 0 --> 2 real roots that are different
