SOLUTION: "where would you expect the vertex on the graph of y = (x - 4)^2 + 5 to be?"

Algebra ->  Algebra  -> Quadratic Equations and Parabolas -> SOLUTION: "where would you expect the vertex on the graph of y = (x - 4)^2 + 5 to be?"      Log On

Ad: You enter your algebra equation or inequality - Algebrator solves it step-by-step while providing clear explanations. Free on-line demo .
Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!
Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!

   

Question 1063: "where would you expect the vertex on the graph of y = (x - 4)^2 + 5 to be?"
Answer by usyim88hk(157) About Me  (Show Source):
You can put this solution on YOUR website!
First, look at the general vertex form of parabola
:
y = (x-h)^2+k
:
where h is the location of the point on x-axis and k is the location of the point of the y-axis. So in your equation, y = (x-4)^2+5, the vertex is gonna be (4,5). Let me show u the graph...
:
graph%28200%2C400%2C-20%2C20%2C-100%2C100%2C%28x-4%29%5E2%2B5%29