SOLUTION: The width of a rectangle is 1 inch less than twice the side of a square. the length of a rectangle is three times the side of the square. if the area of the rectangle is 36 in.² m

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: The width of a rectangle is 1 inch less than twice the side of a square. the length of a rectangle is three times the side of the square. if the area of the rectangle is 36 in.² m      Log On


   

Question 1059606: The width of a rectangle is 1 inch less than twice the side of a square. the length of a rectangle is three times the side of the square. if the area of the rectangle is 36 in.² more than the area of the square then find the side of the square
Answer by josgarithmetic(39616) About Me  (Show Source):
You can put this solution on YOUR website!
Same rectangle? Dimensions w and L.
Let the side length for the square be x.

system%28w=-1%2B2x%2CL=3x%2CwL=36%2Bx%5E2%29

Minor simplification, system%28w=2x-1%2CL=3x%2CwL=x%5E2%2B36%29

Substitutions into the area equation:
%282x-1%29%283x%29=x%5E2%2B36
and you can simplify and solve this.