SOLUTION: What is the maximum value and range of the function y=-2x^2+32x-12

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Question 1058485: What is the maximum value and range of the function y=-2x^2+32x-12
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Convert to vertex form,
y=-2x%5E2%2B32x-12
y=-2%28x%5E2-16x%29-12
y=-2%28x%5E2-16x%2B64%29-12%2B2%2864%29
y=-2%28x-8%29%5E2-12%2B128
y=-2%28x-8%29%5E2%2B116
The vertex is (8,116) and the parabola opens downwards.
y%5Bmax%5D=116
Range is (-infinity,116]