SOLUTION: find the determinant; identify nature of the roots; if D=0 or D>0, find the roots.
1. 4x^2=12x-9
2. 6x^2-x-2=0
3. 52/x - 5.2(x+5) =52
4. 1+ x^2
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Quadratic Equations and Parabolas
-> SOLUTION: find the determinant; identify nature of the roots; if D=0 or D>0, find the roots.
1. 4x^2=12x-9
2. 6x^2-x-2=0
3. 52/x - 5.2(x+5) =52
4. 1+ x^2
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Question 1052778: find the determinant; identify nature of the roots; if D=0 or D>0, find the roots.
1. 4x^2=12x-9
2. 6x^2-x-2=0
3. 52/x - 5.2(x+5) =52
4. 1+ x^2 Answer by ikleyn(52778) (Show Source):
1. To write it in the general form = 0.
2. To calculate the discriminant D = .
3. If D > 0 then the equation has two different real roots.
If D = 0, then the equation has only one real root.
If D < 0, then the equation does not have real roots.
Instead, it has two complex roots.
Do not try to shift your work to our shoulders.
Do it yourself.
Do not forget to send "Thank you" to me for clear instructions.
And the last note: what you called "determinant" in your post, is actually "discriminant".
