SOLUTION: Problem: The height (H) of the ball thrown into the air with an initial velocity of 9.8 m/s from a height of 2 m above the ground is given by the equation H(t)=-4.9t^2+9.8t+2, wher

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Problem: The height (H) of the ball thrown into the air with an initial velocity of 9.8 m/s from a height of 2 m above the ground is given by the equation H(t)=-4.9t^2+9.8t+2, wher      Log On


   

Question 1044182: Problem: The height (H) of the ball thrown into the air with an initial velocity of 9.8 m/s from a height of 2 m above the ground is given by the equation H(t)=-4.9t^2+9.8t+2, where t is the time in seconds that the ball has been in the air
Question: Find the value of t to determine the time it takes the ball to reach 4 m
Answer by ikleyn(52779) About Me  (Show Source):
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Problem: The height (H) of the ball thrown into the air with an initial velocity of 9.8 m/s from a height of 2 m above
the ground is given by the equation H(t)=-4.9t^2+9.8t+2, where t is the time in seconds that the ball has been in the air
Question: Find the value of t to determine the time it takes the ball to reach 4 m
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For it, you need to solve this equation

-4.9t^2+9.8t+2 = 4.

Apply the quadratic formula. You will get two solution: one for the ball moving up, and the second for the ball moving down.