Question 1043210: Could you help me solve this please?
a) 
b) 
is the answer -0.8696
c) 
is the answer: 1.588
Thank you so much
Found 2 solutions by stanbon, ikleyn:
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Could you help me solve this please?
a) 9^(7-3x) =5
(7-3x)*log(9) = log(5)
7-3x = log(5)/log(9)
7-3x = 0.7325
3x = 6.2675
x = 2.0892
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b) log0.135
is the answer -0.8696
Yes, or -0.8697 if you round off
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c) log(7,22) = log7(22) = log(22)/log(7) = 1.588
is the answer: 1.588
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Cheers,
Stan H.
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Answer by ikleyn(52777)  (Show Source):
You can put this solution on YOUR website! Could you help me solve this please?
a)
b) <<<--- To solve it, apply your calculator or computer . . . Or apply special tables for logarithms, if you have it.
It is the only way in this case. // The other way is to expand it in series, but nobody will do it in our days.
When you ask other people to do it for you, you simply shift/move your work to their shoulders.
It is not a job for tutors. It is your work.
is the answer -0.8696
c) <<<--- Apply the formula for the base change for logarithms,  , and you will get =  with decimal logarithms.
See the lesson Change of Base Formula for logarithms in this site.
is the answer: 1.588
Thank you so much
On logarithms, read the lessons
- WHAT IS the logarithm,
- Properties of the logarithm,
- Change of Base Formula for logarithms,
- Solving logarithmic equations,
- Using logarithms to solve real world problems
in this site.
You also have free of charge Online textbook on Algebra-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK
in this site.
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