SOLUTION: The quadratic equation {{{2x^2 + 4x + p=0}}} has roots {{{alpha}}} and {{{beta}}}, and the equation {{{x^2+4x+6 = 0}}} has roots {{{k/alpha}}} and {{{k/beta}}}. Find the values of

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: The quadratic equation {{{2x^2 + 4x + p=0}}} has roots {{{alpha}}} and {{{beta}}}, and the equation {{{x^2+4x+6 = 0}}} has roots {{{k/alpha}}} and {{{k/beta}}}. Find the values of      Log On


   



Question 1041380: The quadratic equation 2x%5E2+%2B+4x+%2B+p=0 has roots alpha and beta, and the equation x%5E2%2B4x%2B6+=+0 has roots k%2Falpha and k%2Fbeta. Find the values of k and p.
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
2x%5E2+%2B+4x+%2B+p=0 <==> x%5E2+%2B+2x+%2B+p%2F2=0
==> -2+=+alpha+%2B+beta and alpha%2Abeta+=+p%2F2.
Now, x%5E2%2B4x%2B6+=+0 ==> -4+=+k%2Falpha+%2B+k%2Fbeta
<==> -4+=+%28k%28alpha%2Bbeta%29%29%2F%28alpha%2Abeta%29%29
==> -4+=+%28k%2A-2%29%2F%28p%2F2%29 ==> k = p, after clearing fractions and simplifying.
Also, from the given, 6++=%28k%2Falpha%29%2A%28k%2Fbeta%29+=+k%5E2%2F%28alpha%2Abeta%29
==> 6%2Aalpha%2Abeta+=+k%5E2 ==> 6%2A%28p%2F2%29+=+k%5E2%7D%0D%0A%0D%0A==%3E+%7B%7B%7B3p+=+k%5E2 ===> 3p+=+p%5E2 ===> p = 0,3.
p = 0 is not acceptable because it will imply a root of 0 in 2x%5E2+%2B+4x+%2B+p=0 and an undefined root in x%5E2%2B4x%2B6+=+0.
Therefore, highlight%28k+=+p+=+3%29.