SOLUTION: \[f(\sqrt{x + 1}) = \frac{1}{x}\] for all $x \ge -1,$ $x\neq 0.$ Find $f(2)$.
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-> SOLUTION: \[f(\sqrt{x + 1}) = \frac{1}{x}\] for all $x \ge -1,$ $x\neq 0.$ Find $f(2)$.
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Question 1041054
:
\[f(\sqrt{x + 1}) = \frac{1}{x}\]
for all $x \ge -1,$ $x\neq 0.$ Find $f(2)$.
Answer by
MaxWong(38)
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To find f(2), We have to set sqrt(x+1) = 2
f(sqrt(x+1))=1/x
f(sqrt(3+1))= 1/3
Therefore f(2) = 1/3