SOLUTION: Let me try this again as I did not recieve the normal confirmation page that this was sent to the wonderful tutors here. Directions from my Professor are as follows: Make sur

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Let me try this again as I did not recieve the normal confirmation page that this was sent to the wonderful tutors here. Directions from my Professor are as follows: Make sur      Log On


   

Question 103813This question is from textbook Intermediate Algebra
: Let me try this again as I did not recieve the normal confirmation page that this was sent to the wonderful tutors here.
Directions from my Professor are as follows:
Make sure that your work is demonstrating the solving method given in the instructions. Use the Insert and Symbols menus in Word to present the radical √ and plus/minus ± symbols. Remember that radicands must be enclosed within [ ]. Typing your work vertically is preferred but optional. If you choose to type horizontally, make sure you are appropriately using grouping symbols.
On Pg: 583 of our textbook it shows the quadratic formula. But I somehow am messing up to the point I am so confused I don't know where to begin.
Here is the Problem:
Solve by using the Quadratic Formula;
x^2 - 3x = 7x - 2 Thank You! This question is from textbook Intermediate Algebra

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
+x%5E2+-+3x+=+7x+-2 Start with the given equation


+x%5E2+-+3x+-7x%2B2=0 Get all terms to one side


+x%5E2+-+10x%2B2=0 Combine like terms


Solved by pluggable solver: Quadratic Formula
Let's use the quadratic formula to solve for x:


Starting with the general quadratic


ax%5E2%2Bbx%2Bc=0


the general solution using the quadratic equation is:


x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29




So lets solve x%5E2-10%2Ax%2B2=0 ( notice a=1, b=-10, and c=2)





x+=+%28--10+%2B-+sqrt%28+%28-10%29%5E2-4%2A1%2A2+%29%29%2F%282%2A1%29 Plug in a=1, b=-10, and c=2




x+=+%2810+%2B-+sqrt%28+%28-10%29%5E2-4%2A1%2A2+%29%29%2F%282%2A1%29 Negate -10 to get 10




x+=+%2810+%2B-+sqrt%28+100-4%2A1%2A2+%29%29%2F%282%2A1%29 Square -10 to get 100 (note: remember when you square -10, you must square the negative as well. This is because %28-10%29%5E2=-10%2A-10=100.)




x+=+%2810+%2B-+sqrt%28+100%2B-8+%29%29%2F%282%2A1%29 Multiply -4%2A2%2A1 to get -8




x+=+%2810+%2B-+sqrt%28+92+%29%29%2F%282%2A1%29 Combine like terms in the radicand (everything under the square root)




x+=+%2810+%2B-+2%2Asqrt%2823%29%29%2F%282%2A1%29 Simplify the square root (note: If you need help with simplifying the square root, check out this solver)




x+=+%2810+%2B-+2%2Asqrt%2823%29%29%2F2 Multiply 2 and 1 to get 2


So now the expression breaks down into two parts


x+=+%2810+%2B+2%2Asqrt%2823%29%29%2F2 or x+=+%2810+-+2%2Asqrt%2823%29%29%2F2



Now break up the fraction



x=%2B10%2F2%2B2%2Asqrt%2823%29%2F2 or x=%2B10%2F2-2%2Asqrt%2823%29%2F2



Simplify



x=5%2Bsqrt%2823%29 or x=5-sqrt%2823%29



So the solutions are:

x=5%2Bsqrt%2823%29 or x=5-sqrt%2823%29