SOLUTION: I am working on solving quadratic equations with substitutions. (y-10/y)^2-6(y'10/y)-27=0 I have done the substitution step, letting (y-10/y)=W. I solved for W. W=9 or -3 from w

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: I am working on solving quadratic equations with substitutions. (y-10/y)^2-6(y'10/y)-27=0 I have done the substitution step, letting (y-10/y)=W. I solved for W. W=9 or -3 from w      Log On


   



Question 1034532: I am working on solving quadratic equations with substitutions.
(y-10/y)^2-6(y'10/y)-27=0
I have done the substitution step, letting (y-10/y)=W. I solved for W. W=9 or -3 from what I got. Now I am having difficulty inputting those answers back into the equation to solve for y. y-10/y=9 or y-10/y=-3. Any help is greatly appreciated. Thank you

Answer by ikleyn(52785) About Me  (Show Source):
You can put this solution on YOUR website!
.
I am working on solving quadratic equations with substitutions.
(y-10/y)^2-6(y'10/y)-27=0
I have done the substitution step, letting (y-10/y)=W. I solved for W. W=9 or -3 from what I got.
Now I am having difficulty inputting those answers back into the equation to solve for y. y-10/y=9 or y-10/y=-3.
Any help is greatly appreciated. Thank you
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%28y-10%29%2Fy = 9  --->  multiply both sides by y  --->

y - 10 = 9y,

-10 = 9y - y,

-10 = 8y,

y = -10%2F8.

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%28y-10%29%2Fy = -3  --->  multiply both sides by y  --->

y - 10 = -3y,

-10 = -3y - y,

-10 = -4y,

y = 10%2F4.