SOLUTION: (t-4)^6-11(t-4)^3+28=0

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Question 1033541: (t-4)^6-11(t-4)^3+28=0
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
This is factorable in the "variable" %28t-4%29%5E3.

%28%28t-4%29%5E3-4%29%28%28t-4%29%5E3-7%29=0

Either %28t-4%29%5E3=4 or %28t-4%29%5E3=7.
Now continue on to solve for t.