SOLUTION: A rectangular piece of metal is 10 in longer than it is wide. Squares with sides 2 in long are cut from the four corners and the flaps are folded upward to form an open box. If the
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Question 1027384: A rectangular piece of metal is 10 in longer than it is wide. Squares with sides 2 in long are cut from the four corners and the flaps are folded upward to form an open box. If the volume of the box is 528in^3, what were the original dimensions of the piece of metal? Answer by josgarithmetic(39617) (Show Source):
You can put this solution on YOUR website! w and L, the dimensions.
L=w+10, and w, again the same dimensions, using the given description.
Folding the flaps, the base of the box is (L-2*2)(w-2*2) inch^2 and the height is 2 inches.
This means the volume is .
Substitute for L, simplify the equation, and solve for w.
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