Question 1015514: Find k if the roots of the equation (k+3)x^2 - 2(k+1)x - (k+1) = 0 are equal. If k is not equal to -3. Found 2 solutions by Boreal, MathTherapy:Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! (k+3)x^2 - 2(k+1)x - (k+1) = 0
if the roots are zero, b^2-4ac=0
b^2=4ac
b^2=(-2(k+1))^2=4k^2+8k+4
4ac=4k^2+16k+12
set them equal
4k^2+8k+4=4k^2+16k+12
8k+4=16k+12
8k=-8
k=-1
2x^2=0
x=0,0