SOLUTION: Problem:
Find the solution to this system of equations both graphically and algebraically. You must show the check step to receive credit.Y=|x-3|+2 and y=-2x+6
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Quadratic Equations and Parabolas
-> SOLUTION: Problem:
Find the solution to this system of equations both graphically and algebraically. You must show the check step to receive credit.Y=|x-3|+2 and y=-2x+6
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Question 1008114: Problem:
Find the solution to this system of equations both graphically and algebraically. You must show the check step to receive credit.Y=|x-3|+2 and y=-2x+6 Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! The first is |x| shifted 3 to the right and up two.
y=|x-3|+2=-2x+6
|x-3|=-2x+4
x-3=-2x+4
3x=7
x=(7/3). This does not work for both original equations.
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x-3=2x-4
x=1
This solves both original equations.
y=4
(1,4)