SOLUTION: "Solve" the following linear system using substitution and interpret the results. (4 marks)
6xy−2x+4==3y+20
Two fractions have denominators 3 and 4 and their sum is 171
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Quadratic Equations and Parabolas
-> SOLUTION: "Solve" the following linear system using substitution and interpret the results. (4 marks)
6xy−2x+4==3y+20
Two fractions have denominators 3 and 4 and their sum is 171
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Question 1007978: "Solve" the following linear system using substitution and interpret the results. (4 marks)
6xy−2x+4==3y+20
Two fractions have denominators 3 and 4 and their sum is 1712. If the numerators are switched, the sum is 32 . Set up a linear system and solve it using elimination to determine the two numerators. (6 marks) Answer by ikleyn(52781) (Show Source):
You can put this solution on YOUR website! .
Two fractions have denominators 3 and 4 and their sum is 1712. If the numerators are switched, the sum is 32 . Set up a linear system and solve it using elimination to determine the two numerators. (6 marks)
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Let x and y be the numerators of the first and the second fraction.
Then you have this system of two equations in two unknowns:
+ = 1712,
+ = 32.
First step to simplify it is to multiply each equation by 12. You will get
4x + 3y = 1712*12
3x + 4y = 32*12.
Can you solve it yourself?
