SOLUTION: If the sides of a square picture frame are increased by 5 cm, the area becomes 289 cm^2. Find the length of a side of the original picture frame.

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: If the sides of a square picture frame are increased by 5 cm, the area becomes 289 cm^2. Find the length of a side of the original picture frame.      Log On


   



Question 100465: If the sides of a square picture frame are increased by 5 cm, the area becomes 289 cm^2. Find the length of a side of the original picture frame.
Found 3 solutions by checkley71, Earlsdon, doukungfoo:
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
(X+5)(X+5)=289
X^2+10X+25=289
X^2+10X+25-289=0
X^2+10X-264=0
(X+22)(X-12)=0
X-12=0
X=12 FOR THE ORIGINAL SIZE OF THE PICTURE
PROOF
(12+5)(12+5)=289
17*17`=289
289=289

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Let the original side length be x.Then,
%28x%2B5%29%5E2+=+289 Solve for x.
x%5E2%2B10x%2B25+=+289 Subtract 289 from both sides.
x%5E2%2B10x-264+=+0 Solve this quadratic equation for x by factoring.
%28x-12%29%28x%2B22%29+=+0
x-12+=+0 so x+=+12 or
x%2B22+=+0 so x+=+-22 Discard the negative solution as the side length is a positive value.
The original side length is 12 cm.
Check:
%28x%2B5%29%5E2+=+%2812%2B5%29%5E2
17%5E2+=+289

Answer by doukungfoo(195) About Me  (Show Source):
You can put this solution on YOUR website!
The area of a square is equal to one of its sides squared
OR
A=S%5E2
This problem states that if the sides of a square are increased by 5 the area becomes 289
so lets plug that information into the formula for area of a square
A=S%5E2
289=%28s%2B5%29%5E2
now just solve for s
first take the square root of both sides of the equal sign
sqrt%28289%29=sqrt%28%28s%2B5%29%5E2%29
17=s%2B5
12=s
so the sides of the original picture frame are 12 cm
Check answer
289=%28s%2B5%29%5E2
289=%2812%2B5%29%5E2
289=%2817%29%5E2
289=289
done!