SOLUTION: What is f(x)=-4x^2-20x+1 in standard form?

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Question 1002735: What is f(x)=-4x^2-20x+1 in standard form?
Found 2 solutions by MathLover1, fcabanski:
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

f%28x%29=-4x%5E2-20x%2B1
The standard form of a quadratic equation looks like this:
ax%5E2%2Bbx%2Bc=0
so, your equation in standard form is: 0=-4x%5E2-20x%2B1 or -4x%5E2-20x%2B1=0

Answer by fcabanski(1391) About Me  (Show Source):
You can put this solution on YOUR website!
Standard form is ax^2 + bx + c. The equation is already in standard form.