SOLUTION: Vertex form of y=3x^2-12x+5 I got (X-2)^2+5/9=y I just want to make sure I'm correct.

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Vertex form of y=3x^2-12x+5 I got (X-2)^2+5/9=y I just want to make sure I'm correct.       Log On


   

Question 1000845: Vertex form of y=3x^2-12x+5 I got (X-2)^2+5/9=y I just want to make sure I'm correct.

Found 2 solutions by MathLover1, MathTherapy:
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!
y=a%28x-h%29%5E2%29%2Bk

y=3x%5E2-12x%2B5
y=%283x%5E2-12x%29%2B5
y=3%28x%5E2-4x%2Bb%5E2%29-3b%5E2%2B5
y=3%28x%5E2-4x%2B2%5E2%29-3%2A2%5E2%2B5
y=3%28x-2%29%5E2%29-3%2A4%2B5
y=3%28x-2%29%5E2%29-12%2B5
y=3%28x-2%29%5E2%29-7
=>h=2 and k=-7
vertex is at:(2,-7)



Answer by MathTherapy(10551) About Me  (Show Source):
You can put this solution on YOUR website!

Vertex form of y=3x^2-12x+5 I got (X-2)^2+5/9=y I just want to make sure I'm correct. 
Nope!!

Vertex form of: y+=+3x%5E2+-+12x+%2B+5 is: highlight_green%28y+=+3%28x+-+2%29%5E2+-+7%29