Questions on Algebra: Quadratic Equation answered by real tutors!

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Question 153542This question is from textbook Intermediate Algebra
: I am stuck on this problem. I did the equation and my answer was y=0,y=9. The problem is to use factoring to solve the equation. 2y^2-162=0
If I'm correct, yea for me!This question is from textbook Intermediate Algebra
: I am stuck on this problem. I did the equation and my answer was y=0,y=9. The problem is to use factoring to solve the equation. 2y^2-162=0
If I'm correct, yea for me!
Answer by Fombitz(1740) About Me  (Show Source):
You can put this solution on YOUR website!
Easiest way is to plug your answer in the original equation.
2y^2-162=0
2(0)^2-162=0
-162=0
Untrue.
y=0 is not a solution.
.
.
.
2y^2-162=0
2(9)^2-162=0
2(81)-162=0
162-162=0
0=0
True.
y=9 is a solution.
.
.
.
You're missing an answer.
2y^2-162=0
2y^2=162
y^2=81
y=0 +- 9
You forgot (-9).
.
.
.
Here's a graph of the function.
graph( 300, 300, -10, 10, -180, 180, 2x^2-162)
Question 153542This question is from textbook Intermediate Algebra
: I am stuck on this problem. I did the equation and my answer was y=0,y=9. The problem is to use factoring to solve the equation. 2y^2-162=0
If I'm correct, yea for me!This question is from textbook Intermediate Algebra
: I am stuck on this problem. I did the equation and my answer was y=0,y=9. The problem is to use factoring to solve the equation. 2y^2-162=0
If I'm correct, yea for me!
Answer by stanbon(18725) About Me  (Show Source):
You can put this solution on YOUR website!
Also y = -9.
Cheers,
Stan H.
Question 153542This question is from textbook Intermediate Algebra
: I am stuck on this problem. I did the equation and my answer was y=0,y=9. The problem is to use factoring to solve the equation. 2y^2-162=0
If I'm correct, yea for me!This question is from textbook Intermediate Algebra
: I am stuck on this problem. I did the equation and my answer was y=0,y=9. The problem is to use factoring to solve the equation. 2y^2-162=0
If I'm correct, yea for me!
Answer by josmiceli(2011) About Me  (Show Source):
You can put this solution on YOUR website!
2y^2 - 162 = 0
I know how to solve it, but I'm not sure what the
"factoring" is about. I guess it means to factor out a 2
from the left side like this:
2(y^2 - 81) = 0
Now if I divide both sides by 2, I get
y^2 - 81 = 0 (since 0/2 = 0)
y^2 = 81
Take the square root of both sides
y = 9
and
y = -9
I think you were half right