SOLUTION: Learning algebra as it applies to electronics. Having trouble with this one because I do not know what to do with the 1/2 shown in the equation. x= -1/ [2phi(FC)1/2]

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Question 70182: Learning algebra as it applies to electronics. Having trouble with this one because I do not know what to do with the 1/2 shown in the equation.
x= -1/ [2phi(FC)1/2]
Answer by bucky(2100) About Me  (Show Source):
You can put this solution on YOUR website!
The exponent of 1%2F2 means take the square root of this quantity. In another form your equation is:
.
x+=+-+1%2F%282%2Aphi%2Asqrt%28FC%29%29
.
Are you sure this equation is correct? phi usually represents magnetic flux or possibly
the phase shift in an a-c voltage. Did you mean pi ... the radian measure of a
circle equivalent to 180 degrees?
.
Also, this is not the equation for the capacitive resistance in an a-c circuit. That equation
is:
.
Xc+=+1%2F%282%2Api%2Af%2AC%29
.
It is also not the equation for the resonant frequency of a series R-L-C circuit.
That equation is:
.
Fo+=+1%2F%282%2Api%2Asqrt%28LC%29%29
.
I'm a little rusty as you can tell, but I don't recall the equation you provided.