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put this solution on YOUR website!The number of bacteria present in a culture after t minutes is given as B=100^ kt. if there are 6231 bacteria present after 11 minutes, find k.
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6231=100^(11k)
Take the log of both sides to get:
log6231 = (11k)log100
3.79456=22k
k=0.1725
Cheers,
Stan H.