SOLUTION: Problem is:(3y/x^4)^-3... I can not figure out how they came up with the answer of x^12/27y^3... I keep coming up with the invert of this answer... I just can't figure out how they

Algebra ->  Algebra  -> Exponents-negative-and-fractional -> SOLUTION: Problem is:(3y/x^4)^-3... I can not figure out how they came up with the answer of x^12/27y^3... I keep coming up with the invert of this answer... I just can't figure out how they      Log On

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Question 23688: Problem is:(3y/x^4)^-3... I can not figure out how they came up with the answer of x^12/27y^3... I keep coming up with the invert of this answer... I just can't figure out how they got it to a positive and inverted it. Thanks for you help.

Answer by rapaljer(4551) About Me  (Show Source):
You can put this solution on YOUR website!
I guess you didn't give the whole problem, so I'll assume there is more to this. However, remember that if you have a fraction raised to the -1 power, it means the reciprocal of the fraction, which means to invert the fraction.

For example, if you had %28a%2Fb%29%5E%28-1%29 this actually means b%2Fa.

R^2 at SCC