SOLUTION: Solve for x where x is a real number 27^2x = 9^x-3

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Question 207533: Solve for x where x is a real number
27^2x = 9^x-3
Answer by stanbon(48575) About Me  (Show Source):
You can put this solution on YOUR website!
Solve for x where x is a real number
27^2x = 9^x-3
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[3^3]^(2x) = [3^2]^(x-3)
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3^(6x) = 3^(2x-6)
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Equate the exponents to get:
6x = 2x-6
4x = -6
x = -3/2
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Cheers,
Stan H.