# SOLUTION: how are you? My first question is #10. ax/b + cx/d = e and #11 a/bx + c/d=e; for both of them i need to solve for X. i dont know how to really disect this problem to solve for X,

Algebra ->  Algebra  -> Exponents-negative-and-fractional -> SOLUTION: how are you? My first question is #10. ax/b + cx/d = e and #11 a/bx + c/d=e; for both of them i need to solve for X. i dont know how to really disect this problem to solve for X,      Log On

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 Algebra: Negative and Fractional exponents Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Exponents-negative-and-fractional Question 148432This question is from textbook algebra the easy way : how are you? My first question is #10. ax/b + cx/d = e and #11 a/bx + c/d=e; for both of them i need to solve for X. i dont know how to really disect this problem to solve for X, dont know each step for this complex fraction equation. Any help at all is greatly appreciated. thank you. -BrianThis question is from textbook algebra the easy way Answer by Alan3354(30993)   (Show Source): You can put this solution on YOUR website!My first question is #10. ax/b + cx/d = e and #11 a/bx + c/d=e; for both of them i need to solve for X. ------------------ 10. ax/b + cx/d = e Multiply by bd to eliminate fractions adx + bcx = bde x*(ad + bc) = bde that's all you can do, no further simplification is possible. ---------- 11. a/bx + c/d=e There's more than one way to go at this, but you get the same answer. a/bx = e - c/d a/bx = (de-c)/d Invert bx/a = d/(de-c) bx = ad/(de-c)