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Question 155616: a)SOLVE 2X^2=6
b) Find the x-intercepts of f(x)=2x^2-6
What are the solutions?
What are the x-intercepts?

Thank you for any help!!!!
: a)SOLVE 2X^2=6
b) Find the x-intercepts of f(x)=2x^2-6
What are the solutions?
What are the x-intercepts?

Thank you for any help!!!!

Answer by jim_thompson5910(9162) About Me  (Show Source):
You can put this solution on YOUR website!
a)

2x^2=6 Start with the given equation


x^2=3 Divide both sides by 2


x=sqrt(3) or x=-sqrt(3) Take the square root of both sides.


So the solutions are x=sqrt(3) or x=-sqrt(3)


which approximate to x=1.732 or x=-1.732


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b)

f(x)=2x^2-6 Start with the given function


0=2x^2-6 Plug in f(x)=0


Notice we have a quadratic equation in the form of ax^2+bx+c where a=2, b=0, and c=-6


Let's use the quadratic formula to solve for x


x = (-b +- sqrt( b^2-4ac ))/(2a) Start with the quadratic formula


x = (-(0) +- sqrt( (0)^2-4(2)(-6) ))/(2(2)) Plug in a=2, b=0, and c=-6


x = (-0 +- sqrt( 0-4(2)(-6) ))/(2(2)) Square 0 to get 0.


x = (-0 +- sqrt( 0--48 ))/(2(2)) Multiply 4(2)(-6) to get -48


x = (-0 +- sqrt( 0+48 ))/(2(2)) Rewrite sqrt(0--48) as sqrt(0+48)


x = (-0 +- sqrt( 48 ))/(2(2)) Add 0 to 48 to get 48


x = (-0 +- sqrt( 48 ))/(4) Multiply 2 and 2 to get 4.


x = (-0 +- 4*sqrt(3))/(4) Simplify the square root (note: If you need help with simplifying square roots, check out this solver)


x = (-0)/(4) +- (4*sqrt(3))/(4) Break up the fraction.


x = 0 +- sqrt(3) Reduce.


x = sqrt(3) or x = -sqrt(3) Break up the "plus/minus" to form two equations.


So the answers are x = sqrt(3) or x = -sqrt(3)


which approximate to x=1.732 or x=-1.732


So this means that the x-intercepts are and

which in decimal form are (1.732,0) and (-1.732,0)


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Notice how the solutions of the first equation are simply the x-coordinates of the x-intercepts.