SOLUTION: A hair breaks under a tension of 1.1 N. What is the diameter of the hair? The tensile strength is 2.0 ✕ 10^8 Pa.

Algebra ->  Testmodule -> SOLUTION: A hair breaks under a tension of 1.1 N. What is the diameter of the hair? The tensile strength is 2.0 ✕ 10^8 Pa.       Log On


   

Question 1161861: A hair breaks under a tension of 1.1 N. What is the diameter of the hair? The tensile strength is 2.0 ✕ 10^8 Pa.
Found 2 solutions by solver91311, ikleyn:
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


You asked a Physics question. This is a Mathematics homework help site. Do you go to the Auto Parts store to buy vegetables?


John

My calculator said it, I believe it, that settles it

Answer by ikleyn(52786) About Me  (Show Source):
You can put this solution on YOUR website!
.

1 Pa = 1 N / 1 m^2.


If d is the diameter of the hair, then


   2%2A10%5E8.pi%2A%28d%5E2%2F4%29 = 1.1 N


which implies


    d%5E2 = %281.1%2A4%29%2F%28pi%2A2%2A10%5E8%29 = %281.1%2A4%29%2F%282%2A3.14%29.10%5E%28-8%29 m^2 = 0.7%2A10-8 m^2.


Hence,


    d = sqrt%280.7%2A10%5E%28-8%29%29 = 0.84%2A10%5E%28-4%29 meters = 0.084 mm.    ANSWER

Solved.

It is very easy. Having a bit of common sense is just enough.