SOLUTION: Consider the function ℎ(𝑥) = (1 + sin 𝜋𝑥) 𝑔(𝑥) . Suppose 𝑔(1) = 2 and 𝑔 ′ (1) = −1. Find ℎ′(1).

Algebra ->  Testmodule -> SOLUTION: Consider the function ℎ(𝑥) = (1 + sin 𝜋𝑥) 𝑔(𝑥) . Suppose 𝑔(1) = 2 and 𝑔 ′ (1) = −1. Find ℎ′(1).      Log On


   

Question 1149907: Consider the function ℎ(𝑥) = (1 + sin 𝜋𝑥)
𝑔(𝑥)
. Suppose 𝑔(1) = 2 and 𝑔
′
(1) = −1. Find
ℎ′(1).
Answer by Edwin McCravy(20055) About Me  (Show Source):
You can put this solution on YOUR website!
Consider the function ℎ(𝑥) = 1 + sin(𝜋𝑥)
Find ℎ′(1).

ℎ(𝑥) =  1 + sin(𝜋𝑥)
ℎ'(𝑥) = 0 + 𝜋∙cos(𝜋𝑥)
ℎ'(1) = 𝜋∙cos(𝜋∙1)
ℎ'(1) = 𝜋∙cos(𝜋)
ℎ'(1) = 𝜋∙(-1)
ℎ'(1) = -𝜋

What's all that about g?  g is not involved with h or h'

Edwin