SOLUTION: Mr. Smith drove 18 mi west. He turned east and drove 30 mi. The whole trip took Mr. Smith 1 1/2 hours. What total distance did Mr. Smith travel? What was Mr. Smith's displacement a

Algebra ->  Test -> SOLUTION: Mr. Smith drove 18 mi west. He turned east and drove 30 mi. The whole trip took Mr. Smith 1 1/2 hours. What total distance did Mr. Smith travel? What was Mr. Smith's displacement a      Log On


   



Question 946120: Mr. Smith drove 18 mi west. He turned east and drove 30 mi. The whole trip took Mr. Smith 1 1/2 hours. What total distance did Mr. Smith travel? What was Mr. Smith's displacement at the end of the motion? What was Mr. Smith's speed? What was Mr. Smith's velocity?
Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
How far did he drive? 18%2B30+=+48 miles
What was his displacement (how far did he end up from where he started)? Well we went 18 miles one way, en back tracked those 18 plus another 12. So he ended up 12 miles west of where he started
Speed? Speed = distance/time = 48/1.5 = 32 miles and hour
velocity? He e3nded up 12 miles west in 1.5 hours. so 12/1.5 = west at 8mph