SOLUTION: Help find two numbers whose sum is 700 and whose product is a maximum.

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Question 873702: Help find two numbers whose sum is 700 and whose product is a maximum.
Found 2 solutions by KMST, Fombitz:
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
x= one of the numbers.
700-x= the other number.
y=x%28700-x%29=700x-x%5E2= the product of those two numbers.
That is a quadratic function, and is usually written as
y=-x%5E2%2B700x .
The graph is a parabola, looking like this: graph%28300%2C300%2C-200%2C800%2C-50000%2C150000%2C-x%5E2%2B700x%29 .
Where is its maximum?
You may have been shown, and it can be proven that the maximum of a quadratic like
y=ax%5E2%2Bbx%2Bc is at x=-b%2F%222+a%22
So in this case the maximum happens when
x=%28-700%29%2F%282%2A%28-1%29%29=%28-700%29%2F%28-2%29=highlight%28350%29 .
Of course, that means that the other number is
700-x=700-350=highlight%28350%29 .
That is not surprising because it is the same as asking you what rectangle with a half-perimeter of 700 has the greatest area, and we know it is a square.
The same problem could also be asked as what is the largest rectangular plot that can be fenced when you have 1400 feet of fencing.

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
A%2BB=700
f=A%2AB
f=A%28700-A%29
f=700A-A%5E2
Find df/dA.
df%2FdA=700-2A
Set it equal to zero to find the maximum.
700-2A=0
2A=700
A=350
B=700-350
B=350