SOLUTION: if f(x)=x^3+3x^2-x+6 a) h(x) which has the same graph as f(x) moved three units down b) m(x) which has the same graph as f(x) moved two units to the right and one unit up

Algebra ->  Test -> SOLUTION: if f(x)=x^3+3x^2-x+6 a) h(x) which has the same graph as f(x) moved three units down b) m(x) which has the same graph as f(x) moved two units to the right and one unit up      Log On


   

Question 813918: if f(x)=x^3+3x^2-x+6
a) h(x) which has the same graph as f(x) moved three units down
b) m(x) which has the same graph as f(x) moved two units to the right and one unit up
Found 2 solutions by josgarithmetic, ewatrrr:
Answer by josgarithmetic(39623) About Me  (Show Source):
You can put this solution on YOUR website!
Let me help just on PART OF question (b).

To move the graph 2 units to the RIGHT, you would do this to x:
(x-2);
that much of the change would be f%28x%29=%28x-2%29%5E3%2B3%28x-2%29%5E2-%28x-2%29%2B6 and you would need to simplify. The proper usage or 'grammar' for this might mean changing the name of the function, or may mean to change what is shown in the argument of f; not sure.

The change vertically is simpler. Move n units up, then increase the ENTIRE expression by n units; move n units down, then decrease the ENTIRE expression by n units.

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

f(x)= x^3+3x^2-x+6  Green

a) h(x)= x^3+3x^2-x+3   |f(x) moved three units down  Blue

b) m(x)= (x-2)^3+3(x-2)^2-(x-2)+7   |f(x) moved 2 units to the right and 1 unit up