SOLUTION: Factor by using trial factors. 2(a+4)^2-(a+4)-3 2(a+4)^2-(a+4)-3= {((a+4)+1)}*{ (2(a+4)-3)}= (a+4)2(a+4) -3(a+4) +2(a+4)+(1*-3) Use the f.o.i.l methods First

Algebra ->  Test -> SOLUTION: Factor by using trial factors. 2(a+4)^2-(a+4)-3 2(a+4)^2-(a+4)-3= {((a+4)+1)}*{ (2(a+4)-3)}= (a+4)2(a+4) -3(a+4) +2(a+4)+(1*-3) Use the f.o.i.l methods First       Log On


   

Question 337270: Factor by using trial factors.
2(a+4)^2-(a+4)-3
2(a+4)^2-(a+4)-3=
{((a+4)+1)}*{ (2(a+4)-3)}=
(a+4)2(a+4) -3(a+4) +2(a+4)+(1*-3)



Use the f.o.i.l methods
First outer inner and last

Found 2 solutions by Fombitz, chiexpert:
Answer by Fombitz(32388) About Me  (Show Source):
Answer by chiexpert(48) About Me  (Show Source):
You can put this solution on YOUR website!
2(a+4)^2-(a+4)-3=
{((a+4)+1)}*{ (2(a+4)-3)}=
(a+4)2(a+4) -3(a+4) +2(a+4)+(1*-3)



Use the f.o.i.l methods
First outer inner and last