SOLUTION: find three positive numbers whose sum is 32 and p =xy^2z is a maximum

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Question 318930: find three positive numbers whose sum is 32 and p =xy^2z is a maximum
Found 2 solutions by Fombitz, Stephen__:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
I'm assuming these numbers need to be integers.
P=xy%5E2z
Since y is squared, you want y to be as large as possible.
The smallest, non-zero value for x and z to have so that y can be maximized is 1.
x=z=1
.
.
.
x%2By%2Bz=32
1%2By%2B1=32
y=30
.
.
.
Pmax=1%2A30%5E2%2A1=900

Answer by Stephen__(1) About Me  (Show Source):
You can put this solution on YOUR website!
I've no idea where to post this but Fombitz's answer is wrong. P is at a maximum at x = 8, y = 16 and z = 8.