Question 312834: A collection of coins is to be divided amongst 3 people so that the second person has 8 more than the first person and the third person has 6 fewer coins than the second,how many coins should each person get?
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! Let x = total number of coins in the collection
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w, y, z, the number of coins had by each person
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A collection of coins is to be divided amongst 3 people so that
"the second person has 8 more than the first person"
y = w+8
Or
w = y-8
;
" and the third person has 6 fewer coins than the second,"
z = y-6
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how many coins should each person get?
:
w + y + z = x
replace w & z
(y-8) + y + (y-6) = x
3y - 14 = x
3y = x + 14
y =  x + 
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We know y > 8 and is an integer, using the above equation:
when x = 13, y = 9
see if that works
w = 9 - 8
w = 1
z = 9 - 6
z = 3
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Total 1 + 9 + 3 = 13
:
However, there are many other solutions
x=16, y=10
x=19, y=11
x=22, y=12 are just a few
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