SOLUTION: What are the points of discontinuity in this relation: 1 / (x^3 - 4x^2) [btw i put it under test cuz idk were this would actually go under]

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Question 280940: What are the points of discontinuity in this relation: 1 / (x^3 - 4x^2)
[btw i put it under test cuz idk were this would actually go under]
Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
graph%28600%2C600%2C-1%2C2%2C-1000%2C1000%2C1%2F%28x%5E3-x%5E2%29%29

The graph of your equation is shown above.

It looks like you have points of discontinuity at x = 0 and x = 1

The points of discontinuity would be when the denominator in the equation equals 0.

Your equation is y = 1/(x^3 - x^2)

The denominator is 0 when x^3 - x^2 = 0

Solve the equation of x^3 - x^2 = 0 to find the points of discontinuity.

x^3 - x^2 factors out to be x^2 * (x-1) = 0

This equation will be true when either x^2 = 0 or when x-1 = 0 or when both are equal to 0.

x^2 = 0 when x = 0.

x-1 = 0 when x = 1.

Your points of discontinuity are when x = 0 and x = 1.

The graph confirms that.