SOLUTION: Here is the full question: Assume that z-scores are normally distributed with a mean of 0 and a standard deviation of 1. If P(z

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Question 1207170: Here is the full question:
Assume that z-scores are normally distributed with a mean of 0 and a standard deviation of 1. If P(z > d) = 0.9926, find d.
d =
Answer by Theo(13342) (Show Source):
You can put this solution on YOUR website!
as i read this, p(z > d) is looking for the probability that the z-score of z is greater than a z-score of d.

if p(z > d) = .9926, then you are looking for the area of .9926 to the right of a z-score of d.

based on my ti-84 plus calculator, d would be equal to a z-score of -2.437236409.

the area to the right of a z-score of -2.437236409 is equal to .9926.

that is the probability that your z-score will be greater than a z=score of -2.437236409.

here's what it looks like on a z-score calculator.

note that most tables give you the area to the left of the z-score.

if you want the area to the right of the z-score, you take the area to the left of the z-score and subtract it from 1.

area to the right of a z-score that is equal to .9926 is the the area of .0074 to the left of the same z-score.

here's what the area to the left of the z-score being equal to .0074 looks like.

SOLUTION: Here is the full question: Assume that z-scores are normally distributed with a mean of 0 and a standard deviation of 1. If P(z > d) = 0.9926, find d. d =