SOLUTION: Two chords and a diameter form a triangle inside a circle. The radius is 5cm and one chord is 2cm longer than the other. Find the perimeter and area of the triangle
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Question 1206348: Two chords and a diameter form a triangle inside a circle. The radius is 5cm and one chord is 2cm longer than the other. Find the perimeter and area of the triangle Found 2 solutions by ikleyn, math_tutor2020:Answer by ikleyn(52788) (Show Source):
The side which is the diameter is 10 = 5*2 cm long.
Two other sides form a right angle, since they lean on the diameter.
So, we have a right-angled triangle with the hypotenuse of 10 cm
and one leg is 2 cm longer than another.
Hence, as probably you just can to guess, this triangle is (3,4,5)-triangle
with the sides 6 cm, 8 cm and 10 cm.
Its perimeter is 6+8+10 = 24 cm.
Its area is = 3*8 = 24 cm^2.
radius = 5
diameter = 2*radius = 2*5 = 10
The diameter is the hypotenuse of the right triangle.
A diameter is a special type of chord that passes through the center. It's the longest chord of the circle.
x = shorter leg of the right triangle
x+2 = longer leg of the right triangle
x > 0 since a negative side length makes no sense.
Due to the Pythagorean Theorem , we can say
Let's expand things out to solve for x. or or
The quadratic formula is an alternative approach.
Ignore the negative result because we stated x > 0 earlier.
leads to
We have a 6-8-10 right triangle.
perimeter = add the sides = 6+8+10 = 24 cm
area = 0.5*base*height = 0.5*6*8 = 24 square cm
This is one of the fairly rare moments when the perimeter and area are the same value (except for the differing unit types of course).