SOLUTION: Given a circle with sector AOB, centre O, radius r cm, where the acute angle AOB is θ radians. Given that the perimeter of the sector is 14 cm and the area of the sector is 10 cm

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Question 1192200: Given a circle with sector AOB, centre O, radius r cm, where the acute angle AOB is θ radians. Given
that the perimeter of the sector is 14 cm and the area of the sector is 10 cm^2, evaluate r and θ

Answer by ikleyn(52800) About Me  (Show Source):
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Given a circle with sector AOB, centre O, radius r cm, where the acute angle AOB is θ radians. Given
that the perimeter of the sector is 14 cm and the area of the sector is 10 cm^2, evaluate r and θ
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The arc length is  r%2Atheta%29;  the sector area is  %281%2F2%29%2Ar%5E2%2Atheta.


Therefore, the equations for the problem are

    2r + r%2Atheta = 14  cm     (the perimeter)    (1)

    %281%2F2%29%2Ar%5E2%2Atheta = 10  cm^2    (the area)        (2)


To find r, multiply equation (1) by r. You will get

    2r%5E2 + r%5E2%2Atheta = 14r.    (3)


In (3), replace  r%5E2%2Atheta by 20, based on (2).  You will get

    2r%5E2 + 20 = 14r,

or

    2r%5E2 - 14r + 20 = 0,

    r%5E2 - 7r + 10 = 0,

    (r-5)*(r-2) = 0,


so the roots of (3) are  r= 2  and  r= 5.


If  r = 2,  then from (2)  theta = 10%2F2 = 5 radians.


If  r = 5,  then from (2)  theta = 10%2F12.5 = 0.8 radians.


Thus the problem has two solutions.


    One solution   is  r= 2 cm,  theta = 5 radians.

    Other solution is  r= 5 cm,  theta = 0.8 radians.

Solved.