SOLUTION: (a) Solve the equation 4y^2 + 3y - 1 = 0.
(b) Use your answer to part (a) to solve the equation 4(2^x)^2 + 3(2^x) - 1 = 0.
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-> SOLUTION: (a) Solve the equation 4y^2 + 3y - 1 = 0.
(b) Use your answer to part (a) to solve the equation 4(2^x)^2 + 3(2^x) - 1 = 0.
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Question 1192197: (a) Solve the equation 4y^2 + 3y - 1 = 0.
(b) Use your answer to part (a) to solve the equation 4(2^x)^2 + 3(2^x) - 1 = 0. Answer by ikleyn(53763) (Show Source):
You can put this solution on YOUR website! .
(a) Solve the equation 4y^2 + 3y - 1 = 0.
(b) Use your answer to part (a) to solve the equation 4(2^x)^2 + 3(2^x) - 1 = 0.
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(a) By using the quadratic formula or by factoring, the roots of the first equation are -1 or 1/4.
(b) Considering as a new variable y, we see that either = -1 or = 1/4.
First equation has no real solutions.
Second equation = 1/4 has the unique solution x= -2.
Therefore, the only solution for part (b) is x= -2.
