SOLUTION: P(x)=x^4-x^3-13x^2+x+12 Find the table of values please i really need it now thank youuuu💕💕

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Question 1188068: P(x)=x^4-x^3-13x^2+x+12
Find the table of values please i really need it now thank youuuu💕💕
Found 3 solutions by MathLover1, Theo, Solver92311:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
P%28x%29=x%5E4-x%5E3-13x%5E2%2Bx%2B12
Find the table of values
just plug in any value of x in given polynomial and calculate P(x)
but, if you factor it completely, you will get roots and you will have four values for x easy to use
P%28x%29=%28x+-+1%29+%28x+%2B+1%29+%28x+%2B+3%29+%28x+-+4%29 => roots are: x=1,+x=-1, x=-3, and x=4
choose some more in between and make a table
x| +P%28x%29
-3|0
-2|+-18.....................P%28x%29=%28-2%29%5E4-%28-2%29%5E3-13%28-2%29%5E2%2B%28-2%29%2B12=-18
-1|0+
0|12.................P%28x%29=%280%29%5E4-%280%29%5E3-13%280%29%5E2%2B%280%29%2B12=12
4| 0
5|192..............P%28x%29=%285%29%5E4-%285%29%5E3-13%285%29%5E2%2B%285%29%2B12=192


Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
the graph of the equation looks like this:



your table of value would probably look like this:



when you draw the graph manually, you plot the points from the table of values and then sketch the graph by connecting the points.

when the table of values changes from positive to negative, that means the graph is crossing the x-axis somewhere in between.

for example:

when x = -4, the graph is positive.
when x = -3, the graph is 0.
when x = -2, the graph i negative.

the graph is crossing the x-axis between x = -4 and x = -2.

you create the table by analyzing the value of p(x) = y at different values of x.

for example, at x = 1, P(x) = y = x^4 - x^3 - 13x^2 + x + 12 becomes 1^4 - 1^3 - 13 * 1^2 + 1 + 12 which becomes 1 - 1 - 13 + 1 + 12 = 0.

this can be seen both on the graph and the table of values.

the coordinate points on the graph are in (x,y) format.
for example, (1,0) means the value of x is 1 and the corresponding value of y is 0 when the value of x is equal to 1.

let me know if you have any questions.

theo

Answer by Solver92311(821) About Me  (Show Source):
You can put this solution on YOUR website!


I have no idea where your table of values is, so I cannot find it for you. You can certainly make your own easily enough though. Select a set of input values. Then, one at a time, substitute each input value for in your function definition. Then do the indicated arithmetic. Build a table that pairs each of your input values with the resulting value of

For example, say you selected the value for one of your input values, then



Which sums to zero.

Therefore one entry in your table would look something like:

           x        P(x)
      ----------------------
      |    1     |    0    |
      ----------------------

You can make the rest of your own table once you decide on the set of input values.

John

My calculator said it, I believe it, that settles it

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