SOLUTION: Solve the simultaneous equation; sin(x + y) = 1/sqrt2; cos2x = - ½. For the value of x,y ranging from 0° to 360°

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Question 1152026: Solve the simultaneous equation;
sin(x + y) = 1/sqrt2;
cos2x = - ½.
For the value of x,y ranging from 0° to 360°

Answer by ikleyn(52788) About Me  (Show Source):
You can put this solution on YOUR website!
.

            This problem is for advanced students.

            Therefore,  I will only show the general direction for you to solve,  leaving the final and detailed implementation to you.


From  sin(x+y) = 1%2Fsqrt%282%29 = sqrt%282%29%2F2,  it follows that

    x + y = 45°    OR   x + y = 135°.



From  cos(2x) = - 1%2F2,  it follows that  

    2x = 120°      OR   2x = 240°,   i.e.

     x = 60°       OR    x = 120°.


Therefore, you need to solve 4 (four) systems of equations


     1)  x + y =  45   (mod 360)
         x     =  60   (mod 360)


     2)  x + y = 135   (mod 360)
         x     =  60   (mod 360)


     3)  x + y =  45   (mod 360)
         x     = 120   (mod 360)


     4)  x + y = 135   (mod 360)
         x     = 120   (mod 360)


Solution of each and every system  1)  to  4)  is an elementary task.


The solution to the original problem will be the union of the solutions of partial problems  1) - 4).