Question 1150956: A rectangular area of 1,050 square feet is to be enclosed by a fence, then divided down the middle by another piece of fence. The fence down the middle costs $0.50 per running foot, and the other fence costs $1.50 per running foot. Find the minimum cost for the required fence.
Answer by ikleyn(52788) (Show Source):
You can put this solution on YOUR website! .
From the context, the dimensions of the rectangle are not given for advance - they are unknowns and they should be found
from the minimum cost condition.
Let x be one dimension and y be the other dimension of the rectangle.
Then the cost of the outside perimeter fence is 1.50*(2x+2y) dollars = 3*(x+y) dollars,
while the cost of the fence down middle is 0.50*x dollars.
Note, that I don't know now, which dimension will be the length and which be the width.
When the problem will be solved, the solution will tell me it . . .
So, I need minimize the function
f(x,y) = 3*(x+y) + 0.5x (1)
under the condition
x*y = 1050. (2)
From (2), express y = and substitute it into (1). You will get
g(x) = = + + .
Differentiate it over x
g'(x) = - +
and equate the derivative to zero. You will get
3.5 = , or
3.5x^2 = 3150
x^2 = = 900,
x = = 30.
Thus the dimensions of the rectangle are 30 ft and = 35 ft.
The fence down middle has the length of 30 ft; hence, it is parallel to the shorter side of the rectangle.
Solved.
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If you want to see many other similar solved problems, look into the lesson
- Calculus optimization problems
in this site.
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